Zoom Logo

ECOP CT-6 - Shared screen with speaker view
Bhavya Pratap Singh
Can you explain the trade-off between growth and reproduction through your model? What I got that both of them follow the same pattern (in cycles) when resources deplete to resources replenish.
Rafael Menezes
Thank you very much for your talk, did you consider to apply this model for microbial populations?
Rafael Menezes
For instance as studied by C. Mulder and J. Hendriks, also in NL
Jasper Croll
Dear Bhavya Pratap Singt, The tradeoff between growth and reproduction emerges from the Energy Budget model because an individual can only spend the energy they acquire through assimilation, which is limited by the resource density and competition in the environment. The cycles indeed both occur because the population is limited by the resource in the environment. But in reproduction driven cycles individuals have enough food to grow towards the size at maturation, but do not have enough energy to directly reproduce. while in the growth driven cycles individuals do not have enough food to growth towards maturity but once they mature they have enough food to reproduce directly
Jasper Croll
Dear Rafael Menezes, I am not very familiar with work on microbal populations. Am I correct that Mulder and Hendriks also work on allometric scaling between species? This is a very interesting discussion, because this is likely to affect the extract shape of the bifurcations I showed, although I expect that a shift in growth plasticity still strongly affect the tradeoff between growth and reproduction.
Rafael Menezes
Yes, I was actually thinking about the allometries :)I think Mulder especially would have data on growth rates of soil organisms of multiple sizes
Juliana Berbert
Does your model assume that the communication is equal in both ways xi -> xj and xj-xi? I mean, there are no individual signaling?
Subekshya Bidari
Hi Juliana! Each individual can have their own coupling strength (kappa) that they attract other’s belief with, communication is one way kappa_i(x_i=x_j) and kappa_j(x_j - x_i)
Juliana Berbert
Thank you, Subekshya.